JEE MATHEMATICS MCQ: INCREASING & DECREASING

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The longest distance of the point

\left( {a,\;0} \right)

from the curve

2{x^2} + {y^2} - 2\;x = 0

, is given by

View answer and explanation

Correct option: D

\sqrt {1 - 2\;a + 2\;{a^2}}

Option D (

\sqrt {1 - 2\;a + 2\;{a^2}}

) is correct because it represents the maximum distance calculated by finding the critical point of the distance function.

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f\left( x \right) = \frac{{K\sin x + 2\cos x}}{{\sin x + \cos x}}

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\left( { - \infty ,\;\infty } \right)