JEE PHYSICS MCQ: ATOMS

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Application +4 | -1

\alpha

-particle after passing through a potential difference of

V

volts collides with a nucleus. If the atomic number of the nucleus is

{Z}

then the distance of closest approach of

\alpha

-particle to the nucleus will be

View answer and explanation

Correct option: B

14.4 \frac{Z}{V} m

Option B (

\left(\frac{\cos \beta}{\cos \alpha}\right)^2

) is correct because the ratio of kinetic energies is the square of the ratio of the cosine of the angles, derived from the conservation of momentum in the x-direction.

More Questions from ATOMS

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The de-Broglie wavelength of an electron in the first Bohr orbit is The volume occupied by an atom is greater than the volume of the nucleus by a factor of about For a hydrogen atom, when electron jump from

n

=2

{n}=1

, then wave length of radiation emitted found to be

\lambda_0

. Then, for which transition of electron of a 'He' atom, the wavelength of radiation emitted will be equal to '

\lambda_0

'. Energy of characteristic X-ray is a consequence of Taking Rydberg’s constant

{R_H} = 1.097\,\, \times \,\,{10^7}\,\,m

, first and second wavelength of Balmer series in hydrogen spectrum is When hydrogen atom is in its first excited level, its radius is its ground state radius