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NEET UG CHEMISTRY MCQ: HYDROCARBONS

1 Hard
1 of 1
Analyzing +4 | -1
Which is the most suitable reagent among the following to distinguish compound (3) from rest of the compounds?
i)    CH3−C≡C−CH3\mathrm{i)}\,\,\,\,C{H_3} - C \equiv C - C{H_3}
ii)    CH3−CH2−CH2−CH3\mathrm{ii)}\,\,\,\,C{H_3} - C{H_2} - C{H_2} - C{H_3}
iii)    CH3−CH2C≡CH\mathrm{iii)}\,\,\,\,C{H_3} - C{H_2}C \equiv CH
iv)    CH3−CH=CH2.\mathrm{iv)}\,\,\,\,C{H_3} - CH = C{H_2}.
View answer and explanation
Correct option: D
Ammonical silver nitrate
Option D is correct because ammoniacal silver nitrate reacts specifically with terminal alkynes (like compound iii) to form a precipitate, while it does not react with internal alkynes, alkanes, or alkenes.

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