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JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

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A\mathrm{A} and B\mathrm{B} formed in the following reactions are:

CrO2Cl2+4NaOH→A+2NaCl+2H2OA+2HCl+2H2O2→B+3H2O\begin{aligned} & \mathrm{CrO}_2 \mathrm{Cl}_2+4 \mathrm{NaOH} \rightarrow \mathrm{A}+2 \mathrm{NaCl}+2 \mathrm{H}_2 \mathrm{O} \\ & \mathrm{A}+2 \mathrm{HCl}+2 \mathrm{H}_2 \mathrm{O}_2 \rightarrow \mathrm{B}+3 \mathrm{H}_2 \mathrm{O} \end{aligned}
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Correct option: A
A=Na2CrO4, B=CrO5\mathrm{A}=\mathrm{Na}_2 \mathrm{CrO}_4, \mathrm{~B}=\mathrm{CrO}_5
Option A (A=Na2CrO4, B=CrO5\mathrm{A}=\mathrm{Na}_2 \mathrm{CrO}_4, \mathrm{~B}=\mathrm{CrO}_5) is correct because the reaction of chromyl chloride with NaOH forms sodium chromate, and the subsequent reaction with HCl and H2O2 forms chromium pentoxide.

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