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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The sum to nn terms of the series 43+109+2827+...\frac{4}{3} + \frac{{10}}{9} + \frac{{28}}{{27}} + ... is
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Correct option: B
3n(2n+1)−12(3n)\frac{{{3^n}\left( {2n + 1} \right) - 1}}{{2\left( {{3^n}} \right)}}
Option B is correct because the sum is calculated by separating the series into two parts: a constant series and a geometric series, and then summing each part.

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