A current of ${\rm{1}}{\rm{.5}}\,\,{\rm{A}}$ flows through a copper voltameter. The thickness of copper deposited on the electrode surface of size $50\,\,{\rm{cm}}\,\, \times \,10\,\,{\rm{cm}}$ is ${\rm{20}}\,\,{\rm{min}}$ will be (density of copper $ = 9000\,\,{\rm{kg}} - {{\rm{m}}^{ - 3}}\,\,{\rm{and}}\,{\rm{ ECE }}\,{\rm{of}}\,{\rm{ copper}} = 0.00033\,\,{\rm{g}}\,\,{{\rm{C}}^{ - 1}})$

$3.3\,\, \times \,\,{10^{ - 6}}\,\,{\rm{m}}$

$1.3\,\,\, \times \,\,{10^{ - 5}}\,\,{\rm{m}}$

$2.6\,\,\, \times \,\,{10^{ - 5}}\,\,{\rm{m}}$

NEET UG PHYSICS MCQ: CURRENT ELECTRICITY

1 Medium

1 of 1

Application +4 | -1

A current of

\mathrm{1}\mathrm{.5}\,\,\mathrm{A}

flows through a copper voltameter. The thickness of copper deposited on the electrode surface of size

50\,\,\mathrm{cm}\,\, \times \,10\,\,\mathrm{cm}

\mathrm{20}\,\,\mathrm{min}

will be (density of copper

= 9000\,\,\mathrm{kg} - {\mathrm{m}^{ - 3}}\,\,\mathrm{and}\,\mathrm{ ECE }\,\mathrm{of}\,\mathrm{ copper} = 0.00033\,\,\mathrm{g}\,\,{\mathrm{C}^{ - 1}})

View answer and explanation

Correct option: B

1.32{\mkern 1mu} {\mkern 1mu} \times {\mkern 1mu} {\mkern 1mu} {10^{ - 6}}\,\,m

Option B (

1.32 \times {10^{ - 6}}\,m

) is correct because it is the calculated thickness of copper deposited using Faraday's laws of electrolysis.

Practice All Chapter MCQs →

T

\mathrm{quantity}\,\,\mathrm{/}\,\mathrm{quantities}

\mathrm{is}\,\,\mathrm{/}\,\,\mathrm{are}