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JEE PHYSICS MCQ: OSCILLATIONS

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A particle of mass 1 kg is moving in SHM with an amplitude 0.02 m and a frequency of 60 Hz. The maximum force in newton acting on the particle is
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Correct option: C
288  π2288\,\,{\pi ^2}
Option C (288π2288\pi ^2) is correct because the maximum force is calculated using the formula Fmax=mω2a=m4π2f2aF_{max} = m\omega^2a = m4\pi^2f^2a.

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