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JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1
A quantity xx is given by x = IFv2WL4x\, = \,\frac{{IF{v^2}}}{{W{L^4}}} where, II is moment of inertia, FF is force, vv is work and LL is length. The dimensional formula for xx is same as that of
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Correct option: D
energy density
Option D (energy density) is correct because the dimensional formula for x matches the dimensional formula for energy density.

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