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NEET UG CHEMISTRY MCQ: HYDROCARBONS

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Application +4 | -1
At constant temperature and pressure, the percentage of butane by volume in a mixture of butane, propane and propyne is 40%.40 \%. What will be the volume of CO2(g)\mathrm{CO}_{2(\mathrm{g})} (in ml) under same pressure and temperature produced, when 150 ml of gaseous mixture is burnt in excess of O2?\mathrm{O}_2?
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Correct option: C
510 ml
Option C (510 ml) is correct because it is calculated based on the combustion equations of butane, propane, and propyne, considering the given percentage of butane.

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