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JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1
Let ff is twice differentiable on RR such that f(0)=1,f′(0)=0f(0)=1, f^{\prime}(0)=0 and f′′(0)=−1f^{\prime \prime}(0)=-1, then for a ∈R\in R, lim⁡x→∞(f(ax))x=\lim _{x \rightarrow \infty}\left(f\left(\frac{a}{\sqrt{x}}\right)\right)^x=
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Correct option: C
ea22e^{\frac{a^2}{2}}
Option C (ea22e^{\frac{a^2}{2}}) is correct because it is the limit calculated using L'Hôpital's rule and the given conditions.

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