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JEE CHEMISTRY MCQ: S-BLOCK ELEMENTS

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Analyzing +4 | -1

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : LiF is sparingly soluble in water.
Reason R : The ionic radius of

L{i^ + }

ion is smallest
among its group members, hence has least
hydration enthalpy.
In the light of the above statements, choose the
most appropriate answer from the options given
below.

View answer and explanation

Correct option: C

A is true but R is false.

Option C (A is true but R is false) is correct because LiF is sparingly soluble due to high lattice enthalpy, and

Li^+

has high hydration enthalpy due to its small size.

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Assertion (A): Among the alkali metals, lithium salts exhibit the least electrical condutance in aqueous solutions.
Reason (R): Smaller the radius of the hydrated cation, lower is the electrical conductance in aqueous solutions.

(A)

is a ternary salt with divalent cation.

(A)

gives yellow ppt. with

\mathrm{K}_2 \mathrm{CrO}_4

as well as with

\mathrm{AgNO}_3

. (A) is precipitated by

\mathrm{H}_2 \mathrm{~S}

neither in acidic nor ammoniacal medium, but addition of

\left(\mathrm{NH}_4\right)_2 \mathrm{CO}_3

\mathrm{NH}_4 \mathrm{OH}

gave white ppt. (B).

0.297 \mathrm{~g}

(A)

0.197 \mathrm{~g}

(B)

(A)

. In the Down’s cell

\mathrm{KCl}

\mathrm{NaCl}

to: Which of the alkali metal is having least melting point? Fusion mixture is comprised of: Statement 1:

{LiCl}

is predominatly a covalent compound.

Statement 2: Electronegativity difference between

{Li}

{Cl}