JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

The sum to

n

terms of the series

\frac{3}{1^2}+\frac{5}{1^2+2^2}+\frac{7}{1^2+2^2+3^2}+\ldots

View answer and explanation

Correct option: A

\frac{6 n}{n+1}

Option A (

\frac{{6 n}}{{n+1}}

) is correct because the series can be simplified to a telescoping series, and the sum to

n

terms is

\frac{{6n}}{{n+1}}

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