$\mathop {\lim }\limits_{x \to 2} = \frac{{\sqrt {1 + \sqrt {2 + x} } - \sqrt 3 }}{{x - 2}}$ is equal to

JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

\lim\limits_{x \to 2} = \frac{{\sqrt {1 + \sqrt {2 + x} } - \sqrt 3 }}{{x - 2}}

is equal to

View answer and explanation

Correct option: A

\frac{1}{{8\sqrt 3 }}

Option A (

\frac{1}{{8\sqrt 3 }}

) is correct because after rationalizing and applying the limit, the expression evaluates to this value.

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