JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1

Let

a, b, c

be the lengths of the sides of a triangle (no two of them are equal) and

k \in R

. If the roots of the equation

x^2+2(a+b+c) x+6 k(a b+b c+c a)=0

are real, then:

View answer and explanation

Correct option: A

k<\frac{2}{3}

Option A (

k<\frac{2}{3}

) is correct because the discriminant of the quadratic equation must be non-negative for real roots, leading to the inequality

k < \frac{2}{3}

More Questions from QUADRATIC EQUATIONS

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{x^2} - px + q = 0

{\alpha _1},{\beta _1}

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{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

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9{x^2} - 18\left| x \right| + 5 = 0

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