JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

The value of

\int\limits_{{1 / \pi}}^{2 / \pi} \frac{\sin 1 / x}{x^2} \mathrm{~d} x

is equal

View answer and explanation

Correct option: A

Option A (1) is correct because substituting

t = \frac{{1}}{{x}}

transforms the integral to

\int_{\pi/2}^{\pi} \sin(t) dt

, which evaluates to 1.

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