JEE PHYSICS MCQ: CURRENT ELECTRICITY

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The Avogadro’s number is

6\,\, \times \,\,{10^{23}}

per gm mole and electronic charge is

1.6\,\, \times \,\,{10^{ - 19}}\,\,C

. The Faraday’s number is

View answer and explanation

Correct option: A

6\,\, \times \,\,{10^{23}}\,\, \times \,\,1.6\,\, \times \,\,{10^{ - 19}}

Option A (

6 \times {10^{23}} \times 1.6 \times {10^{ - 19}}

) is correct because Faraday's constant is the product of Avogadro's number and the elementary charge.

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