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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
If roots of the equation x3−12  x2+39  x−28=0{x^3} - 12\;{x^2} + 39\;x - 28 = 0 are in A.P., then their common difference will be
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Correct option: C
±3\pm 3
Option C (±3\pm 3) is correct because substituting the roots in A.P. into the cubic equation allows us to solve for the common difference.

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