JEE MATHEMATICS MCQ: PARABOLA

1 Easy

1 of 1

Application +4 | -1

A line

L

passing through the focus of the parabola

{\left( {y - 2} \right)^2} = 4\left( {x + 1} \right)

intersects the parabola in two distinct points. If m be the slope of the line

L

, then

View answer and explanation

Correct option: C

m \in \left( { - \infty ,0} \right) \cup \left( {0,\infty } \right)

Option C (

m \in ( - \infty ,0) \cup (0,\infty )

) is correct because any line passing through the focus of a parabola intersects it at two distinct points, except for the line parallel to the axis (which has a slope of 0).

More Questions from PARABOLA

Practice All Chapter MCQs →

The equation of a common tangent to the parabolas

y=x^2

and

y=-(x-2)^2

is A point

P

moves such that slope of one tangent drawn from it to parabola

y^2=16 x

is four times the slope of other tangent, then the length of latus rectum of the conic represented by locus of

P

, is Let

P,Q,R

be three points on parabola

{y^2} = 4x

and normal at

P

and

R

meet at

Q

, then the locus of the mid-point of the chord

PR

is a parabola whose vertex is at The tangents at the end points of any chord through

(1,0)

to the parabola

y^2+4 x=8

intersect The focus of the parabola

x^2=-16 y

is If

I

denotes the semi-latusrectum of the parabola

{y^2} = 4ax

and

SP

and

SQ

denote the segments of any focal chord

PQ,S

being the focus, then

SP,l

and

SQ

are in the relation