JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int_0^{20 \pi}(|\sin x|+|\cos x|)^2 d x

is equal to

View answer and explanation

Correct option: D

20(\pi+2)

The correct answer is D (

20(\pi+2)

) because it is the result of evaluating the definite integral

\int_0^{20 \pi}(|\sin x|+|\cos x|)^2 dx

as shown in the step-by-step solution.

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