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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Limn→∞[1n2sec⁡21n2+2n2sec⁡24n2……+.+1nsec⁡21]  equals\mathop {{\text{Lim}}}\limits_{n \to \infty } \left[ {\frac{1}{{{n^2}}}{{\sec }^2}\frac{1}{{{n^2}}} + \frac{2}{{{n^2}}}{{\sec }^2}\frac{4}{{{n^2}}} \ldots \ldots + . + \frac{1}{n}{{\sec }^2}1} \right]\,\,{\text{equals}}
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Correct option: D
12tan⁡1\frac{1}{2} \tan 1
Option D (12tan⁡1\frac{1}{2} \tan 1) is correct because the limit can be expressed as a definite integral, which evaluates to 12tan⁡1\frac{1}{2} \tan 1.

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