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JEE CHEMISTRY MCQ: THERMODYNAMICS

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Understanding +4 | -1
If enthalpy of combustion of CC (graphite) is x(ย kJ/mol)x({~kJ} / {mol}) then enthalpy of formation (in kJ/mol{kJ} / {mol} ) of CO2(ย g){CO}_2({~g}) will be

(Given : Enthalpy of sublimation of C(s)C(s) is yโ€‰kJ/mol{y}\, {kJ} / {mol} )
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Correct option: A
xx
Option A (xx) is correct because the enthalpy of formation of CO2(g)CO_2(g) is equal to the enthalpy of combustion of C(graphite)C(graphite).

More Questions from THERMODYNAMICS

Practice All Chapter MCQs โ†’
Consider following reactions
I: ย C(s)+12O2(ย g)โˆ’CO(g),ฮ”H1=a\ \mathrm{C}(\mathrm{s})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})-\mathrm{CO}(\mathrm{g}), \Delta \mathrm{H}_1=\mathrm{a}

II: CO(g)+12O2(ย g)โˆ’CO2(ย g),ฮ”H2=b\mathrm{CO}(\mathrm{g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})-\mathrm{CO}_2(\mathrm{~g}), \Delta \mathrm{H}_2=\mathrm{b}

III: C(s)+CO2(ย g)โˆ’2CO(g);ฮ”H3=c\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{~g})-2 \mathrm{CO}(\mathrm{g}) ; \Delta \mathrm{H}_3=\mathrm{c}
Select the correct statement
When 0.18ย g0.18 \mathrm{~g} of glucose was burnt in a bomb calorimeter, the temperature rose by 4ย K.4 \mathrm{~K}. The heat capacity of the calorimeter system is (ฮ”CHโˆ˜=โˆ’2.8ร—106ย J/molย glucose)\left(\Delta_{\mathrm{C}} \text{H}^{\circ}=-2.8\times 10^6 \mathrm{~J} / \mathrm{mol} \text{ glucose}\right) Statement-1: CsI{CsI} is less soluble in water compared to CsCl{CsCl}
Satement-2: More amount of heat is liberated during the formation of CsCl{CsCl} than the formation CsI{Cs} I from their elements
Consider the following processes :

ฮ”H(KJ/mol)1/2Aโ†’B+1503Bโ†’2C+Dโˆ’125E+Aโ†’2D+350\begin{array}{cccccccccccccccccccc} {}&{\Delta H(KJ/mol)} \\ {1/2A \to B}&{ + 150} \\ {3B \to 2C + D}&{ - 125} \\ {E + A \to 2D}&{ + 350} \end{array}

For B+Dโ†’E+2C,ฮ”H{B}+{D} \rightarrow {E}+2 {C}, \Delta {H} will be :
The difference b/w ฮ”H\Delta H and ฮ”u\Delta u at constant volume is equal to The heat evolved in the combustion of methane is given by the following equations CH4(g)+2O2(g)โ†’CO2(g)+H2O(l);ฮ”H=โˆ’890.3kJ\mathrm{C}{\mathrm{H}_4}\left( \mathrm{g} \right) + 2{\mathrm{O}_2}\left( \mathrm{g} \right) \to \mathrm{C}{\mathrm{O}_2}\left( \mathrm{g} \right) + {\mathrm{H}_2}\mathrm{O}\left( l \right);\Delta H = - 890.3\mathrm{kJ} How many grams of methane would be required to produce 44.15 kJ of heat of combustion?
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