$A B C$ is a right angled isosceles triangle, right angled at $A(2,1)$. If the equation of side $B C$ is $-2 x+y=3$, then the combined equation of lines $A B$ and $A C$ is

$3 x^2-3 y^2+8 x y+20 x+10 y+25=0$

$3 x^2-3 y^2+8 x y-20 x-10 y+25=0$

$3 x^2-3 y^2+8 x y+10 x+15 y+20=0$

JEE MATHEMATICS MCQ: STRAIGHT LINES

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Analyzing +4 | -1

A B C

is a right angled isosceles triangle, right angled at

A(2,1)

. If the equation of side

B C

-2 x+y=3

, then the combined equation of lines

A B

and

A C

View answer and explanation

Correct option: D

None of the above

The correct answer is None of the above because the combined equation of lines AB and AC is

3x^2 - 8xy - 3y^2 - 4x + 22y - 7 = 0

, which is not among the options.

Practice All Chapter MCQs →

x-3 y=p, a x+2 y=q

a x+y=r

\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

(3,8)

x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0