${\rm{Si}}{{\rm{F}}_4}$ gets hydrolysed giving

${{\rm{H}}_2}{\rm{Si}}{{\rm{F}}_6}$

${\rm{Si}}{\left( {{\rm{OH}}} \right)_4}$

${\rm{Si}}{\left( {{\rm{OH}}} \right)_2}{{\rm{F}}_2}$

NEET UG CHEMISTRY MCQ: 14 TH GROUP ELEMENTS (P-BLOCK)

1 Easy

1 of 1

Understanding +4 | -1

\mathrm{Si}{\mathrm{F}_4}

gets hydrolysed giving

View answer and explanation

Correct option: D

{\mathrm{H}_2}\mathrm{Si}{\mathrm{F}_6}

Option D (

{\mathrm{H}_2}\mathrm{Si}{\mathrm{F}_6}

) is correct because

\mathrm{Si}{\mathrm{F}_4}

hydrolyzes to form silicic acid and hydrofluorosilicic acid (

{\mathrm{H}_2}\mathrm{Si}{\mathrm{F}_6}