JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Analyzing +4 | -1

x_1

and

x_2

are two positive values of

x

for which

2 \cos x,|\cos x|

and

3 \sin ^2 x-2

are in GP. The minimum value of

\left|x_1-x_2\right|

View answer and explanation

Correct option: C

2 \cos ^{-1}\left(\frac{2}{3}\right)

Option C (

2 \cos ^{-1}\left(\frac{2}{3}\right)

) is correct because it represents the minimum difference between two positive values of x that satisfy the given geometric progression condition.

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