JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Analyzing +4 | -1

I_1=\lim \limits_{{x \rightarrow \infty}}\left(\tan ^{-1} \pi x-\tan ^{-1} x\right) \cos x

and

I_2=\lim \limits_{{x \rightarrow 0}}\left(\tan ^{-1} \pi x-\tan ^{-1} x\right) \cos x

, then

\left(I_1, I_2\right)

View answer and explanation

Correct option: A

(0,0)

Option A ((0,0)) is correct because both limits

I_1

and

I_2

evaluate to 0.

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