NEET UG CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

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Analyzing +4 | -1

{M^{ + 3}}

ion has the electronic configuration as

\left[ {Xe} \right]\,\,5{d^{10}}4{f^{14}}6{s^2},

hence the element

M

belongs to

View answer and explanation

Correct option: B

p-block

The correct answer is p-block (B) because the electronic configuration of

M^{+3}

[Xe] 4f^{14} 5d^{10} 6s^2

, adding back the 3 electrons gives a configuration ending in

6s^2 6p^1

, indicating a p-block element.

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