JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

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Application +4 | -1

S_{n}=\sum_{r=0}^{n} \frac{1}{{ }^{n} C_{r}}

and

t_{n}=\sum_{r=0}^{n} \frac{r}{{ }^{n} C_{r}}

, then

\frac{t_{n}}{S_{n}}

is equal to

View answer and explanation

Correct option: D

\frac{1}{2} n

Option C (

\frac{n^{2}(n+1)}{2}

) is correct because it correctly calculates the sum of the series when n is odd, using the given sum for when n is even.

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