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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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For y=f(x)=∫0x 2 ∣ t ∣ dty = f\left( x \right) = \int \limits_0^x \,2\,\left| {\,t\,} \right|\,dt, the tangent lines parallel to the bisector of the first quadrant angle are
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Correct option: A
y=x  ±  14y = x\,\, \pm \,\,\frac{1}{4}
Option A (y=x  ±  14y = x\,\, \pm \,\,\frac{1}{4}) is correct because the tangent lines parallel to the bisector of the first quadrant are found by setting the derivative equal to 1 and solving for x.

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