Skip to main content
Back to TRIGONOMETRIC EQUATIONS

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy
1 of 1
Application +4 | -1
If sin⁡θ+cosec⁡θ=2\sin \theta+\operatorname{cosec} \theta=2, then cos⁡2015θ+cosec⁡2015θ\cos ^{2015} \theta+\operatorname{cosec}^{2015} \theta is equal to:
View answer and explanation
Correct option: C
1
Option C (1) is correct because if sin⁡θ+csc⁡θ=2\sin \theta + \csc \theta = 2, then sin⁡θ=1\sin \theta = 1, which implies cos⁡θ=0\cos \theta = 0 and csc⁡θ=1\csc \theta = 1. Therefore, cos⁡2015θ+csc⁡2015θ=0+1=1\cos^{2015} \theta + \csc^{2015} \theta = 0 + 1 = 1.

More Questions from TRIGONOMETRIC EQUATIONS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.