The enthalpy of vapourisation of a certain liquid at its boiling point of ${35^0}C$ is $24.64\,\,KJ/mol$. The value of change in entropy for the process is

$704\,\,J{K^{ - 1}}mo{l^{ - 1}}$

$24.64\,\,J{K^{ - 1}}mo{l^{ - 1}}$

$7.04\,\,J{K^{ - 1}}mo{l^{ - 1}}$

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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The enthalpy of vapourisation of a certain liquid at its boiling point of

{35^0}C

24.64\,\,KJ/mol

. The value of change in entropy for the process is

View answer and explanation

Correct option: B

80\,\,J{K^{ - 1}}mo{l^{ - 1}}

Option B (

80\,J{K^{ - 1}}mo{l^{ - 1}}

) is correct because it is the result of dividing the enthalpy of vaporization by the boiling point in Kelvin.

Practice All Chapter MCQs →

{T_i}

{T_f}

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

\Delta G