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JEE MATHEMATICS MCQ: THEORY OF EQUATION

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Application +4 | -1
Let α,β,δ\alpha ,\beta ,\delta be the roots of x4+x2+1=0.{x^4} + {x^2} + 1 = 0. Then, the equation whose roots are α2,β2,γ2,δ2{\alpha ^2},{\beta ^2},{\gamma ^2},{\delta ^2} is
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Correct option: B
(x2+x+1)2=0{\left( {{x^2} + x + 1} \right)^2} = 0
The correct answer is B ((x2+x+1)2=0{\left( {{x^2} + x + 1} \right)^2} = 0) because substituting y=x2y = x^2 transforms the equation and squaring the result gives the desired equation.

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