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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1
Let x=α+β,  y=αω+βω2,  z=αω2+βω,  ωx = \alpha + \beta ,\;y = \alpha \omega + \beta {\omega ^2},\;z = \alpha {\omega ^2} + \beta \omega ,\;\omega is an imaginary cube root of unity. The value of xyzxyz is
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Correct option: C
α3+β3{\alpha ^3} + {\beta ^3}
Option C (α3+β3{\alpha ^3} + {\beta ^3}) is correct because substituting the given expressions for x,y,zx, y, z and using the properties of cube roots of unity simplifies the product xyzxyz to α3+β3\alpha^3 + \beta^3.

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