Molar conductivities (${\mathop {\rm{\Lambda }}\limits^ \circ _m}$) at infinite dilution of ${\rm{NaCl}},{\rm{HCl}}$ and ${\rm{C}}{{\rm{H}}_3}{\rm{COONa}}$ are 126.4, 425.9 and 91.0 ${\rm{S {\kern 1pt} {\kern 1pt}c}}{{\rm{m}}^2}{\kern 1pt} {\rm{mo}}{{\rm{l}}^{ - 1}}$ respectively.${\mathop {\rm{\Lambda }}\limits^ \circ _m}$ for ${\rm{C}}{{\rm{H}}_3}{\rm{COOH}}$ will be :

390.5 ${\rm{S {\kern 1pt} {\kern 1pt}c}}{{\rm{m}}^2}{\kern 1pt} {\rm{mo}}{{\rm{l}}^{ - 1}}$

425.5 ${\rm{S {\kern 1pt} {\kern 1pt}c}}{{\rm{m}}^2}{\kern 1pt} {\rm{mo}}{{\rm{l}}^{ - 1}}$

180.5 ${\rm{S {\kern 1pt} {\kern 1pt}c}}{{\rm{m}}^2}{\kern 1pt} {\rm{mo}}{{\rm{l}}^{ - 1}}$

290.8 ${\rm{S {\kern 1pt} {\kern 1pt}c}}{{\rm{m}}^2}{\kern 1pt} {\rm{mo}}{{\rm{l}}^{ - 1}}$

JEE CHEMISTRY MCQ: ELECTRO CHEMISTRY

1 Easy

1 of 1

Application +4 | -1

Molar conductivities (

{\mathop \mathrm{\Lambda }\limits^ \circ _m}

) at infinite dilution of

\mathrm{NaCl},\mathrm{HCl}

and

\mathrm{C}{\mathrm{H}_3}\mathrm{COONa}

are 126.4, 425.9 and 91.0

{\rm{S {\kern 1pt} {\kern 1pt}c}}{\mathrm{m}^2}{\kern 1pt} \mathrm{mo}{\mathrm{l}^{ - 1}}

respectively.

{\mathop \mathrm{\Lambda }\limits^ \circ _m}

for

\mathrm{C}{\mathrm{H}_3}\mathrm{COOH}

will be :

View answer and explanation

Correct option: D

390.5

{\rm{S {\kern 1pt} {\kern 1pt}c}}{\mathrm{m}^2}{\kern 1pt} \mathrm{mo}{\mathrm{l}^{ - 1}}

Option D (390.5 S cm² mol⁻¹) is correct because it is calculated using Kohlrausch's Law of Independent Migration of Ions.

Practice All Chapter MCQs →

25^{\circ} \mathrm{C}

0.295 \mathrm{~V}

{p_1}{\kern 1pt} {\kern 1pt} \mathrm{and}{\kern 1pt} {\kern 1pt} {p_2}

\mathop {\mathrm{Pt}\left( {{\mathrm{H}_2}} \right)}\limits_{{p_1}} \left| {\mathop {{\mathrm{H}^ + }\left( {aq} \right)}\limits_{1\mathrm{ }M} } \right|\mathop {Pt\left( {{\mathrm{H}_2}} \right)}\limits_{{p_2}}

\mathrm{CuS}{\mathrm{O}_4}

{AlCl}_3

STP

({F}=96500 {C})

2 \mathrm{Ag}(\mathrm{s})+\mathrm{S}^{2-}(\mathrm{aq}) \rightarrow \mathrm{Ag}_2 \mathrm{S}(\mathrm{s})+2 \mathrm{e}^{-}

\mathrm{pH}=3

0.1 \mathrm{~M}-\mathrm{H}_2 \mathrm{S},

\mathrm{H}_2 \mathrm{S}, K_{\mathrm{a}_1}=10^{-8} ; K_{\mathrm{a}_2}=10^{-13}, K_{\mathrm{sp}}

\mathrm{Ag}_2 \mathrm{S}=4 \times 10^{-48},

E^{\circ}_{{\mathrm{Ag} | \mathrm{Ag}}^{+}}=0.80 \mathrm{~V},

\log 2=0.3,

2.303 R T / F=0.06