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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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The standard heat of combustion of solid boron is :
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Correct option: D
−12ΔfΔH∘(B2O3)- \frac{1}{2}{\Delta _f}\Delta H^\circ \left( {{\mathrm{B}_2}{\mathrm{O}_3}} \right)
Option D (−12ΔfΔH∘(B2O3)- \frac{1}{2}{\Delta _f}\Delta H^\circ \left( {{\mathrm{B}_2}{\mathrm{O}_3}} \right)) is correct because the standard heat of combustion of solid boron is related to the formation of B2O3, considering the stoichiometry of the reaction.

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