At STP, the order of root mean square velocities of molecules of ${{\rm{H}}_2},{{\rm{N}}_2},{{\rm{O}}_2}$ and ${\rm{HBr}}$ is

${{\rm{H}}_2} > {{\rm{N}}_2} > {{\rm{O}}_2} > HBr$

${\rm{HBr}} > {{\rm{O}}_2} > {{\rm{N}}_2} > {{\rm{H}}_2}$

${\rm{HBr}} > {{\rm{H}}_2} > {{\rm{O}}_2} > {{\rm{N}}_2}$

${{\rm{N}}_2} > {{\rm{O}}_2} > {{\rm{H}}_2} > HBr$

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NEET UG CHEMISTRY MCQ: STATES OF MATTER

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Application +4 | -1

At STP, the order of root mean square velocities of molecules of

{\mathrm{H}_2},{\mathrm{N}_2},{\mathrm{O}_2}

and

\mathrm{HBr}

View answer and explanation

Correct option: A

{\mathrm{H}_2} > {\mathrm{N}_2} > {\mathrm{O}_2} > HBr

Option A (

{\mathrm{H}_2} > {\mathrm{N}_2} > {\mathrm{O}_2} > HBr

) is correct because the root mean square velocity is inversely proportional to the square root of the molar mass. Therefore, the gas with the lowest molar mass will have the highest RMS velocity.

NEET UG CHEMISTRY MCQ: STATES OF MATTER

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