JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

Let

x^{2}+x+1

be divisible by 3 . If

x

is divided by 3 , the remainder will be

View answer and explanation

Correct option: B

Option B (1) is correct because when x is divided by 3, the remainder is 1, satisfying the given condition that

x^2 + x + 1

is divisible by 3.

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{x^2} - px + q = 0

{\alpha _1},{\beta _1}

{x^2} - qx + p = 0,

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{x^2} + 4ax + 2 > 0

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a

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9{x^2} - 18\left| x \right| + 5 = 0

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