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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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The energy of electron in first Bohr’s orbit of H-atom is – 13.6 eV. What will be its potential energy in

n = {4^{th}}

orbit

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Correct option: D

– 1.70 eV

Option D (– 1.70 eV) is correct because the potential energy is twice the total energy, and the total energy in the nth orbit is given by

E_n = E_1/n^2

.

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