Skip to main content
Back to STRUCTURE OF ATOM

NEET UG CHEMISTRY MCQ: STRUCTURE OF ATOM

1 Medium
1 of 1
Application +4 | -1
When the frequency of light incident on a metallic plate is doubled, the KE of the emitted photoelectrons will be:
View answer and explanation
Correct option: C
Increased but more than doubled of the previous KE
Option C (Increased but more than doubled of the previous KE) is correct because the kinetic energy is related to the frequency by KE=hf−WKE = hf - W, where W is the work function. Doubling the frequency does not simply double the kinetic energy.

More Questions from STRUCTURE OF ATOM

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.