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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1
If asin⁡−1x−bcos⁡−1x=ca \sin ^{-1} x-b \cos ^{-1} x=c, then asin⁡−1x+a \sin ^{-1} x+ bcos⁡−1xb \cos ^{-1} x is equal to
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Correct option: D
πab+c(a−b)a+b\frac{\pi a b+c(a-b)}{a+b}
Option D (πab+c(a−b)a+b\frac{\pi a b+c(a-b)}{a+b}) is correct because by solving the system of equations, we can find the value of the expression.

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