NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

1 Easy

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Application +4 | -1

The displacement of an oscillating particle is given by

y=A \sin (B x+C t+D)

. The dimensional formula for

(A B C D)

View answer and explanation

Correct option: B

\left[\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^{-1}\right]

Option B (

\left[\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^{-1}\right]

) is correct because the argument of the sine function must be dimensionless, implying B has dimensions of

L^{-1}

and C has dimensions of

T^{-1}

. A has dimensions of L. Therefore, the product ABCD has dimensions of

L \times L^{-1} \times T^{-1} \times 1 = T^{-1}

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