JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1

Equation of a tangent to the ellipse

\frac{x^2}{36}+\frac{y^2}{25}=1

, passing through the point where a directrix of the ellipse meets the + ve

x

-axis is

View answer and explanation

Correct option: C

6 y+\sqrt{11} x=36

Option C (

6 y+\sqrt{11} x=36

) is correct because it represents the tangent to the ellipse passing through the point where the directrix meets the positive x-axis.

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\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1

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O