Skip to main content
Back to PERMUTATIONS

JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy
1 of 1
Application +4 | -1
The number of ways to 16 different things to three persons A,B,CA, B, C so that BB gets one more than AA and CC gets two more than BB, is
View answer and explanation
Correct option: A
16!4!5!7!\frac{16 !}{4 ! 5 ! 7 !}
Option A (16!4!5!7!\frac{{16 !}}{{{{4 ! 5 ! 7 !}}}}) is correct because it represents the number of ways to divide 16 distinct items into groups of 4, 5, and 7.

More Questions from PERMUTATIONS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
šŸ”“

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.