Eight drops of a density ρ and each of radius a are falling through air with a constant velocity $375{\rm{cm}}{{\rm{s}}^{ - 1}}$). When the eight drops coalesce to from a single drop the terminal velocity of the new drop will be

$15 \times {10^{ - 2}}{\rm{m}}{{\rm{s}}^{ - 1}}$

$1.5 \times {10^{ - 2}}{\rm{m}}{{\rm{s}}^{ - 1}}$

$2.4 \times {10^{ - 2}}{\rm{m}}{{\rm{s}}^{ - 1}}$

$0.75 \times {10^{ - 2}}{\rm{m}}{{\rm{s}}^{ - 1}}$

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NEET UG PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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Application +4 | -1

Eight drops of a density ρ and each of radius a are falling through air with a constant velocity

375\mathrm{cm}{\mathrm{s}^{ - 1}}

). When the eight drops coalesce to from a single drop the terminal velocity of the new drop will be

View answer and explanation

Correct option: D

15 \times {10^{ - 2}}\mathrm{m}{\mathrm{s}^{ - 1}}

Option C (A is true but R is false) is correct because kerosene oil spreading on water is due to lower surface tension, not just the existence of surface tension.

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