${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{SiC}}{{\rm{l}}_2}$ undergoes hydrolysis but ${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{CC}}{{\rm{l}}_2}$ does not why?

Only 3p orbital is involved in C

${\rm{Si}} - {\rm{Cl}}$ bond is more polar than ${\rm{C}} - {\rm{Cl}}$ bond

NEET UG CHEMISTRY MCQ: 14 TH GROUP ELEMENTS (P-BLOCK)

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Understanding +4 | -1

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{SiC}{\mathrm{l}_2}

undergoes hydrolysis but

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{CC}{\mathrm{l}_2}

does not why?

View answer and explanation

Correct option: A

Low lying d-orbitals present in Si but not in C

Option A is correct because silicon has low-lying d-orbitals that can accept electron pairs from water during hydrolysis, while carbon does not.