JEE CHEMISTRY MCQ: HYDROCARBONS

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Butyne-1 and butyne-2 can be distinguished by:

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Correct option: D

Ammoniacal cuprous chloride

Option D (Ammoniacal cuprous chloride) is correct because terminal alkynes (butyne-1) react with ammoniacal cuprous chloride to form a red precipitate, while internal alkynes (butyne-2) do not.

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\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

\sigma

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