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NEET UG PHYSICS MCQ: WAVE OPTICS

1 Easy

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Application +4 | -1

A microwave of wavelength

2.0 \mathrm{~cm}

falls normally on a slit of width

4.0 \mathrm{~cm}

. The angular spread of the central maxima of the diffraction pattern obtained on a screen

1.5 \mathrm{~m}

away from the slit, will be

View answer and explanation

Correct option: C

60^{\circ}

Option C (

60^{\circ}

) is correct because the angular spread of the central maxima is given by

2\theta

, where

\sin \theta = \frac{\lambda}{a}

.

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