The maximum value of $a \cos x+b \sin x$ is

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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The maximum value of

a \cos x+b \sin x

View answer and explanation

Correct option: D

\left(a^2+b^2\right)^{1 / 2}

Option D (

\left(a^2+b^2\right)^{1 / 2}

) is correct because the maximum value of

a \cos x + b \sin x

\sqrt{{a^2 + b^2}}

Practice All Chapter MCQs →

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\triangle A B C

C

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\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=