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JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1
If the line xcos⁡α+ysin⁡a=px\cos \alpha + y\sin \mathrm{a} = p be normal to the ellipse x2a2+y2b2=1\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1, then
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Correct option: D
p2(a2sec⁡2α+b2cosec2α)=(a2−b2)2{p^2}({a^2}{\sec ^2}\alpha + {b^2}cose{c^2}\alpha ) = {\left( {{a^2} - {b^2}} \right)^2}
Option D (p2(a2sec⁡2α+b2cosec2α)=(a2−b2)2{p^2}({a^2}{\sec ^2}\alpha + {b^2}cose{c^2}\alpha ) = {\left( {{a^2} - {b^2}} \right)^2}) is correct because it represents the condition for the given line to be normal to the ellipse.

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