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NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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E.m.f. of a cell in terms of reduction potential of its left and right electrode is :
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Correct option: C
E=ER−ELE = {E_R} - {E_L}
Option C (E=ER−ELE = {E_R} - {E_L}) is correct because the EMF of a cell is the difference between the reduction potential of the right-hand electrode (cathode) and the left-hand electrode (anode).

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