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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If 0<y<21/30 < y < {2^{1/3}} and x(y3−1)=1x\left( {{y^3} - 1} \right) = 1, then 2x+23x3+25x5+…\frac{2}{x} + \frac{2}{{3{x^3}}} + \frac{2}{{5{x^5}}} + \ldots is equal to
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Correct option: A
log⁡(y32−y3)\log \left( {\frac{{{y^3}}}{{2 - {y^3}}}} \right)
Option A (log⁡(y32−y3)\log \left( {\frac{{{y^3}}}{{2 - {y^3}}}} \right)) is correct because it is derived by substituting x=1y3−1x = \frac{1}{{{y^3} - 1}} into the given series and simplifying using logarithmic properties.

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